CSIR UGC NET 2024, Exam Date, Application Form, Admit Card, Exam Pattern, Result, Eligibility Criteria
National Testing Agency (NTA) conducts CSIR-UGC NET to determine the eligibility ‘for Junior Research Fellowship (JRF) and for Lectureship/Assistant Professor’ in Indian universities and colleges subject to fulfilling the eligibility criteria laid down by UGC. CSIR or Council of Scientific & Industrial Research Human Resource Development Group’s Examination team commences CSIR UGC NET examination for Junior Research Fellowship & Eligibility for Lectureship. This examination is conducted for subjects related to Science and technology. Check Details CSIR UGC NET 2024, Exam Date, Application Form, Admit Card, Exam Pattern, Result, Eligibility Criteria
CSIR NET Highlights 2024
| Exam Name | CSIR UGC NET (Council of Scientific and Industrial Research University Grants Commission National Eligibility Test) |
| Conducting Body | National Testing Agency (NTA) |
| Exam Level | National |
| Exam Frequency | Twice a year |
| Exam Mode | Online only |
CSIR NET Eligibility 2024
The basic CSIR UGC NET eligibility criteria that candidates must fulfill are:
- Candidates should obtain a degree in BTech/BE/BPharma/MBBS/BS (4 years)/Integrated BS-MS/MSc with minimum 55 per cent marks
- To apply for JRF, candidates should be maximum 28 years in age as on December 1, 2019
- There is no upper age limit to apply for the post of lectureship
NTA CSIR UGC NET Exam Pattern 2024
Look at the salient features of NTA CSIR UGC NET 2024 June Examination given in the following section. Also, CSIR NET Exam Pattern 2024 is summarized in the tabular form which is given below.
- A single paper MCQ based test will be held.
- The Test Booklet will be printed in Hindi & English Version.
- The Test Booklet shall be divided into three parts (A, B & C).
- Total marks: 200.
- Exam Duration: 3 hours.
- Negative marking shall be applicable as per subject wise scheme of Exam.
- No grievances/representation with regard to Answer Key(s) after the declaration of result will be entertained.
Joint CSIR UGC NET 2024 Paper Pattern:-
CHEMICAL SCIENCES Paper Pattern
- CHEMICAL SCIENCES: 20 Questions from Part A, 40 Questions from Part B, 60 Questions from Part C (Total Questions : 120)
- Max No of Questions to attempt: 15 Marks from Part A, 35 Marks from Part B, 25 Marks from Part C (Total Number of Questions : 75)
- Marks for each correct answer: 2 Marks from Part A, 2 Marks from Part B, 4 Marks from Part C (Total Number of Questions : 200)
- Marks for each incorrect answer (Negative marking): 0.5 Marks from Part A, 0.5 Marks from Part B, 1 Marks from Part C
CHEMICAL SCIENCES Paper Pattern
- CHEMICAL SCIENCES: 20 Questions from Part A, 40 Questions from Part B, 60 Questions from Part C (Total Questions : 120)
- Max No of Questions to attempt: 15 Marks from Part A, 35 Marks from Part B, 25 Marks from Part C (Total Number of Questions : 75)
- Marks for each correct answer: 2 Marks from Part A, 2 Marks from Part B, 4 Marks from Part C (Total Number of Questions : 200)
- Marks for each incorrect answer (Negative marking): 0.5 Marks from Part A, 0.5 Marks from Part B, 1 Marks from Part C
EARTH, ATMOSPHERIC, OCEAN AND PLANETARY SCIENCES Paper Pattern
- EARTH, ATMOSPHERIC, OCEAN AND PLANETARY SCIENCES: 20 Questions from Part A, 50 Questions from Part B, 80 Questions from Part C (Total Questions : 150)
- Max No of Questions to attempt: 15 Marks from Part A, 35 Marks from Part B, 25 Marks from Part C (Total Number of Questions : 75)
- Marks for each correct answer: 2 Marks from Part A, 2 Marks from Part B, 4 Marks from Part C (Total Number of Questions : 200)
- Marks for each incorrect answer (Negative marking): 0.5 Marks from Part A, 0.5 Marks from Part B, 1.32 Marks from Part C
CHEMICAL SCIENCES Paper Pattern
- CHEMICAL SCIENCES: 20 Questions from Part A, 40 Questions from Part B, 60 Questions from Part C (Total Questions : 120)
- Max No of Questions to attempt: 15 Marks from Part A, 35 Marks from Part B, 25 Marks from Part C (Total Number of Questions : 75)
- Marks for each correct answer: 2 Marks from Part A, 2 Marks from Part B, 4 Marks from Part C (Total Number of Questions : 200)
- Marks for each incorrect answer (Negative marking): 0.5 Marks from Part A, 0.5 Marks from Part B, 1 Marks from Part C
LIFE SCIENCES Paper Pattern
- LIFE SCIENCES: 20 Questions from Part A, 50 Questions from Part B, 75 Questions from Part C (Total Questions : 145)
- Max No of Questions to attempt: 15 Marks from Part A, 35 Marks from Part B, 25 Marks from Part C (Total Number of Questions : 75)
- Marks for each correct answer: 2 Marks from Part A, 2 Marks from Part B, 4 Marks from Part C (Total Number of Questions : 200)
- Marks for each incorrect answer (Negative marking): 0.5 Marks from Part A, 0.5 Marks from Part B, 1 Marks from Part C
MATHEMATICAL SCIENCES Paper Pattern
- MATHEMATICAL SCIENCES: 20 Questions from Part A, 40 Questions from Part B, 60 Questions from Part C (Total Questions : 120)
- Max No of Questions to attempt: 15 Marks from Part A, 25 Marks from Part B, 20 Marks from Part C (Total Number of Questions : 60)
- Marks for each correct answer: 2 Marks from Part A, 3 Marks from Part B, 4.75 Marks from Part C (Total Number of Questions : 200)
- Marks for each incorrect answer (Negative marking): 0.5 Marks from Part A, 0.75 Marks from Part B, 0 Marks from Part C
PHYSICAL SCIENCES Paper Pattern
- PHYSICAL SCIENCES: 20 Questions from Part A, 25 Questions from Part B, 30 Questions from Part C (Total Questions : 75)
- Max No of Questions to attempt: 15 Marks from Part A, 20 Marks from Part B, 20 Marks from Part C (Total Number of Questions : 55)
- Marks for each correct answer: 2 Marks from Part A, 3.5 Marks from Part B, 5Marks from Part C (Total Number of Questions : 200)
- Marks for each incorrect answer (Negative marking): 0.5 Marks from Part A, 0.875 Marks from Part B, 1.25Marks from Part C
UGC NET 2024 Exam Dates
| Events | Dates 2024 (Tentative) | |
| June 2024 | December 2024 | |
| UGC NET 2024 Notification | February 2024 | August 2024 |
| Availability of Online Application | 3rd week of March 2024 | 1st week of September 2024 |
| Last date to apply online | 3rd week of April 2024 | Last week of September 2024 |
| Correction window opens | April 2024 | 3rd to 4th week of October 2024 |
| Availability of Admit card | 3rd week of May 2024 | 3rd week of November 2024 |
| UGC NET 2024 | 3rd to 4th week of June 2024 | 2nd to 3rd week of December 2024 |
| Release of Answer Key | June 2024 | December 2024 |
| Announcement of Results | 1st week of July 2024 | 2nd week of January 2024 |
CSIR UGC NET 2024 Application Form
- CSIR-UGC NET 2024 application form has been available on the website of National Testing Agency.
- Candidates are allowed to fill only one application form.
- The application form is only accepted in online mode, no other mode will be accepted.
- Candidates must provide their register email id and mobile number to get information by email or SMS.
- Candidates cannot withdraw application form once it is submitted successfully.
- Multiple forms submitted by candidates will be rejected.
- The applicants must get the printout of the application form for future use.
Application Fee:
Payment mode: UGC NET application fee can be paid through online mode by Debit or Credit Card/ Net-Banking/ Paytm.
| Category | Application Fee (in Rs.) |
| UR/ General candidates | 1000 |
| General –EWS/ OBC – NCL candidates | 500 |
| ST/ SC/ PWD/ Transgender candidates | 250 |
CSIR UGC NET Result 2024
CSIR UGC NET Result 2024 will be released soon, The National Testing Agency has released the CSIR NET result on csirnet.nta.nic.in. The CSIR UGC NET 2024 result will have the name and roll number of the candidates, CSIR NET 2024 registration number, sections appeared for and mark secured by the candidate in each section, along with the qualifying status of the candidate and the total marks secured.
The candidates can also click on the direct link of the CSIR UGC NET 2024 result given below to access their scorecard directly.
CSIR UGC NET Selection Process
CSIR NET selection process includes the following stages:
- CSIR NET application form: All interested and eligible candidates need to fill CSIR NET 2024 application form on the official website of the exam
- CSIR NET admit card: CSIR UGC NET admit card is released for candidates who successfully submit the application form and pay the exam fee. The admit card is released on the official website of the exam.
- CSIR NET exam: Next, candidates need to appear for CSIR UGC NET exam as per the date and time mentioned on the admit card. CSIR NET is typically conducted twice a year in the months of June and December.
- CSIR NET result: The result for CSIR NET is declared on the official website. Candidates qualifying the NET exam then get eligible for JRF or lectureship
Preparation Tips for UGC NET
- First of all, collect complete information about the examination pattern and syllabus.
- Buy some good reference books which cover the entire syllabus.
- Make study notes and revise them from time to time.
- You can also check previous year exam papers for reference.
- Stay updated with current affairs and general knowledge.
- Always follow your study timetable for better preparation.
UGC NET Admit Card 2024
The admit card for the UGC NET 2024 exam will be issued to those candidates who have submitted the application form for appearing in the entrance test. The admit card will be available one or two weeks prior to the exam on the official website of the NTA NET. Candidates can download the same from the website. Candidates have to bring admit card along with ID proof on the day of the exam.
CSIR-UGC NET Admit Card 2024: How to download
- Visit the official site of CSIR UGC NET on csirnet.nta.nic.in.
- Click on CSIR-UGC NET Admit Card 2024 link available on the home page.
- A new page will open where candidates will have to enter application number, date of birth and security pin and click on submit.
- Your admit card will be displayed on the screen.
- Check the admit card and download it.
- Keep a hard copy of the same for further need
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